# Do first five terms of sequence \left\{\frac{1-(-1)^{n}}{n^{3}}\right\}

Do first five terms of sequence
$\left\{\frac{1-\left(-1{\right)}^{n}}{{n}^{3}}\right\}$
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Given
$\left\{\frac{1-\left(-1{\right)}^{n}}{{n}^{3}}\right\}$
$\left\{\frac{1-\left(-1{\right)}^{1}}{{1}^{3}}\right\}=\frac{1-\left(-1\right)}{1}=2$
$\left\{\frac{1-\left(-1{\right)}^{2}}{{2}^{3}}\right\}\frac{1-\left(1\right)}{8}=0$
$\left\{\frac{1-\left(-1{\right)}^{3}}{{3}^{3}}\right\}\frac{1-\left(-1\right)}{27}=\frac{2}{27}$
$\left\{\frac{1-\left(-1{\right)}^{4}}{{4}^{3}}\right\}\frac{1-\left(-1\right)}{64}=0$
$\left\{\frac{1-\left(-1{\right)}^{5}}{{5}^{3}}\right\}\frac{1-\left(-1\right)}{125}=\frac{2}{125}$