emancipezN
2021-05-14
Answered

Do first five terms of sequence

$\left\{\frac{1-(-1{)}^{n}}{{n}^{3}}\right\}$

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ottcomn

Answered 2021-05-15
Author has **97** answers

Given

$\left\{\frac{1-(-1{)}^{n}}{{n}^{3}}\right\}$

$\left\{\frac{1-(-1{)}^{1}}{{1}^{3}}\right\}=\frac{1-(-1)}{1}=2$

$\left\{\frac{1-(-1{)}^{2}}{{2}^{3}}\right\}\frac{1-(1)}{8}=0$

$\left\{\frac{1-(-1{)}^{3}}{{3}^{3}}\right\}\frac{1-(-1)}{27}=\frac{2}{27}$

$\left\{\frac{1-(-1{)}^{4}}{{4}^{3}}\right\}\frac{1-(-1)}{64}=0$

$\left\{\frac{1-(-1{)}^{5}}{{5}^{3}}\right\}\frac{1-(-1)}{125}=\frac{2}{125}$

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