Question

# Give the first six terms of the following sequences. You can assume that the sequences start with an index of 1. 1) An arithmetic sequence in which the first value is 2 and the common difference is 3. 2) A geometric sequence in which the first value is 27 and the common ratio is \frac{1}{3}

Sequences
Give the first six terms of the following sequences. You can assume that the sequences start with an index of 1.
1) An arithmetic sequence in which the first value is 2 and the common difference is 3.
2) A geometric sequence in which the first value is 27 and the common ratio is $$\frac{1}{3}$$

2021-05-27
1)
The value $$u_1=2$$
Common difference= 3
use the formula
$$u_n=u_1+(n-1)d$$
Replace $$u_1=2, \ d=3$$
$$\Rightarrow u_n=2+(n+1)3$$
$$\Rightarrow 3n-3+2$$
$$\Rightarrow u_n=3n-1$$ $$n=1 \ u_1=2$$
$$n=2 \ u_2=5$$
$$n=3 \ u_3=8$$
$$n=4 \ u_4=11$$
$$n=5 \ u_5=14$$
$$n=6 \ u_6=17$$
2)
a= first term= 27
$$\gamma$$= common ration= $$\frac{1}{3}$$
We know the formula
$$a_n=a\gamma^{n-1}$$
Replace a=27, $$\gamma=\frac{1}{3}$$
$$a_n=27(\frac{1}{3})^{n-1}$$
$$a_n=(3)^{3}(\frac{1}{3})^{n-1}$$ $$a_n=3^{3}\cdot 3^{-(n-1)}$$
$$a_n=3^{4-n}$$ $$a_1=27, \ a_2=9, \ a_3=3, \ a_4=0, \ a_5=\frac{1}{3}, a_6=\frac{1}{9}$$