Step 1

The second question is opinion question and cannot be answered as per bartleby guidelines.

It is given that:

\(\log_{7}(x+2)=\log_{7}(14)−\log_{7}(x−3)\)

use the formula \(\log a−\log b=\log(\frac{a}{b})\) to get:

\(\log_{7}(x+2)=\log_{7}(\frac{14}{x-3})\)

Step 2

Cancel log from both sides to get:

\(x+2=\frac{14}{x-3}\)

(x+2)(x-3)=14

\(x^{2}+2x-3x-6=14\)

\(x^{2}-x-20=0\)

Step 3

Solve the quadratic equation as follows:

\(x^{2}-5x+4x-20=0\)

x(x-5)+4(x-5)=0

(x-5)(x+4)=0

x=5, -4

Hence the values of x are 5 and −4.