# The missing terms for the given polynomal p, q, r, and s such that q neq 0, r neq 0 and s neq 0, frac{p}{q} -: frac{r}{s} = frac{ps}{qr}

Question
Polynomial arithmetic
The missing terms for the given polynomal p, q, r, and s such that
$$q \neq 0, r \neq 0 and s \neq 0, \frac{p}{q} -: \frac{r}{s} = \frac{ps}{qr}$$

2020-11-17
Given polynomial p, q, r, and s such that $$q \neq 0, r \neq 0 and s \neq 0, \frac{p}{q} -: \frac{r}{s} = ?$$
Calculation
The arithmetic operation division is inverse of the arithmetic operation multiplication.
$$\frac{p}{q} -: \frac{r}{s} = \frac{p}{q} \cdot \frac{s}{r}$$
If p, q, r, and s are well defined polynomials, then the above result is true for polynomials.
For polynomial p, q, r, and s such that $$q \neq 0, r \neq 0 and s \neq 0, \frac{p}{q} -: \frac{r}{s} = \frac{ps}{qr}$$
Conclusion: The polynomials p, q, r, and s such that $$q \neq 0, r \neq 0 and s \neq 0, \frac{p}{q} -: \frac{r}{s} = \frac{ps}{qr}$$

### Relevant Questions

The missing terms for the given polynomal p, q, r, and s such that
$$q \neq 0\ \text{and}\ s\neq 0,\ pq \cdot \frac{r}{s}=\frac{pr}{qs}$$
Dayton Power and Light, Inc., has a power plant on the Miami Riverwhere the river is 800 ft wide. To lay a new cable from the plantto a location in the city 2 mi downstream on the opposite sidecosts $180 per foot across the river and$100 per foot along theland.
(a) Suppose that the cable goes from the plant to a point Q on theopposite side that is x ft from the point P directly opposite theplant. Write a function C(x) that gives the cost of laying thecable in terms of the distance x.
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I keep on missing Part D. The answer for part D is not -150,150,-155,108,105( was close but it said not quite check calculations)
Part A
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Express your answer to two significant figures and include the appropriate units.
Part B
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Express your answer to two significant figures and include the appropriate units.
Part C
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Express your answer to two significant figures and include the appropriate units.
Part D
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Part E
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DISCOVER: Nested Form of a Polynomial Expand Q to prove that the polynomials P and Q ae the same $$P(x) = 3x^{4} - 5x^{3} + x^{2} - 3x +5$$
$$Q(x) = (((3x - 5)x + 1)x 3)x + 5$$
Try to evaluate P(2) and Q(2) in your head, using the forms given. Which is easier? Now write the polynomial
R(x) =x^{5} - 2x^{4} + 3x^{3} - 2x^{2} + 3x + 4\) in “nested” form, like the polynomial Q. Use the nested form to find R(3) in your head.
Do you see how calculating with the nested form follows the same arithmetic steps as calculating the value ofa polynomial using synthetic division?
(1 pt) A new software company wants to start selling DVDs withtheir product. The manager notices that when the price for a DVD is19 dollars, the company sells 140 units per week. When the price is28 dollars, the number of DVDs sold decreases to 90 units per week.Answer the following questions:
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B. Write the revenue function, as a function of price. Answer:R(p)=
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If the particle is released from rest at position r0, its speed atposition 2r0, is most nearly
a) $$\displaystyle{\left({\frac{{{8}{U}{o}}}{{{m}}}}\right)}^{{1}}{\left\lbrace/{2}\right\rbrace}$$
b) $$\displaystyle{\left({\frac{{{6}{U}{o}}}{{{m}}}}\right)}^{{\frac{{1}}{{2}}}}$$
c) $$\displaystyle{\left({\frac{{{4}{U}{o}}}{{{m}}}}\right)}^{{\frac{{1}}{{2}}}}$$
d) $$\displaystyle{\left({\frac{{{2}{U}{o}}}{{{m}}}}\right)}^{{\frac{{1}}{{2}}}}$$
e) $$\displaystyle{\left({\frac{{{U}{o}}}{{{m}}}}\right)}^{{\frac{{1}}{{2}}}}$$
if the potential energy function is given by
$$\displaystyle{U}{\left({r}\right)}={b}{r}^{{P}}-\frac{{3}}{{2}}\rbrace+{c}$$
where b and c are constants
which of the following is an edxpression of the force on theparticle?
1) $$\displaystyle{\frac{{{3}{b}}}{{{2}}}}{\left({r}^{{-\frac{{5}}{{2}}}}\right)}$$
2) $$\displaystyle{\frac{{{3}{b}}}{{{2}}}}{\left\lbrace{3}{b}\right\rbrace}{\left\lbrace{2}\right\rbrace}{\left({r}^{{-\frac{{1}}{{2}}}}\right)}$$
3) $$\displaystyle{\frac{{{3}{b}}}{{{2}}}}{\left\lbrace{3}\right\rbrace}{\left\lbrace{2}\right\rbrace}{\left({r}^{{-\frac{{1}}{{2}}}}\right)}$$
4) $$\displaystyle{2}{b}{\left({r}^{{-\frac{{1}}{{2}}}}\right)}+{c}{r}$$
5) $$\displaystyle{\frac{{{3}{b}}}{{{2}}}}{\left\lbrace{2}{b}\right\rbrace}{\left\lbrace{5}\right\rbrace}{\left({r}^{{-\frac{{5}}{{2}}}}\right)}+{c}{r}$$
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A. Find the radii of the two "daughter" nuclei of charge+46e.
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$$\displaystyle{Q}{\left({r},{s}\right)}={\frac{{{e}^{{{r}^{{{e}}}{s}}}}}{{{s}}}}$$
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