Evaluate the following integral: \int \frac{(y-3)}{y^{2}-6y+1}

permaneceerc

permaneceerc

Answered question

2021-05-11

Evaluate the following integral: (y3)y26y+1

Answer & Explanation

Layton

Layton

Skilled2021-05-12Added 89 answers

Substitute y26y+1=t
differentiate it with respect to y,
2y6=dtdy
2(y3)=dtdy
(y3)dy=dt2
Hence the integral becomes:
I=y3y26y+1dy
=12dtt
=12log|t|+c
=12log|y26y+1|+c

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