For the equation (-1,2), y= \frac{1}{2}x - 3, write an equation in slope intercept form for the line that passes through the given point and is parallel to the graph of the given equation.

Step 1
Given point (-1,2) and the line $y=\frac{1}{2}x-3$
Step 2
We know that the slope of two parallel lines are equal.
The slope of the line $y=\frac{1}{2}x-3ism=\frac{1}{2}$
So, the slope of required line is also $m=\frac{1}{2}$. The equation of line is
$y-y_1=m(x-x_1)$
$y-2=\frac{1}{2}(x+1)$
$y-2=\frac{1}{2}x+\frac{1}{2}$
$y=\frac{1}{2}x+\frac{5}{2}$