Given point (-1,2) and the line \(y =\frac{1}{2}x-3\)

Step 2

We know that the slope of two parallel lines are equal.

The slope of the line \(y=\frac{1}{2}x-3 is m = \frac{1}{2}\)

So, the slope of required line is also \(m = \frac{1}{2}\). The equation of line is

\(y-y_{1}=m(x-x_{1})\)

\(y-2=\frac{1}{2}(x+1)\)

\(y-2=\frac{1}{2}x+\frac{1}{2}\)

\(y=\frac{1}{2}x+\frac{5}{2}\)