For the equation (-1,2), y= \frac{1}{2}x - 3, write an equation in slope intercept form for the line that passes through the given point and is parallel to the graph of the given equation.

Question

For the equation (-1,2), y= \frac{1}{2}x - 3, write an equation in slope intercept form for the line that passes through the given point and is parallel to the graph of the given equation.

Expert Answer

pattererX

Answered 2021-05-15 Author has 10748 answers

Step 1
Given point (-1,2) and the line \(y =\frac{1}{2}x-3\)
Step 2
We know that the slope of two parallel lines are equal.
The slope of the line \(y=\frac{1}{2}x-3 is m = \frac{1}{2}\)
So, the slope of required line is also \(m = \frac{1}{2}\). The equation of line is
\(y-y_{1}=m(x-x_{1})\)
\(y-2=\frac{1}{2}(x+1)\)
\(y-2=\frac{1}{2}x+\frac{1}{2}\)
\(y=\frac{1}{2}x+\frac{5}{2}\)

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