# For the equation (-1,2), y= \frac{1}{2}x - 3, write an equation in slope intercept form for the line that passes through the given point and is parallel to the graph of the given equation.

For the equation (-1,2), $$y= \frac{1}{2}x - 3$$, write an equation in slope intercept form for the line that passes through the given point and is parallel to the graph of the given equation.

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pattererX
Step 1
Given point (-1,2) and the line $$y =\frac{1}{2}x-3$$
Step 2
We know that the slope of two parallel lines are equal.
The slope of the line $$y=\frac{1}{2}x-3 is m = \frac{1}{2}$$
So, the slope of required line is also $$m = \frac{1}{2}$$. The equation of line is
$$y-y_{1}=m(x-x_{1})$$
$$y-2=\frac{1}{2}(x+1)$$
$$y-2=\frac{1}{2}x+\frac{1}{2}$$
$$y=\frac{1}{2}x+\frac{5}{2}$$