# For the equation (-1,2), y= \frac{1}{2}x - 3, write an equation in slope intercept form for the line that passes through the given point and is parallel to the graph of the given equation.

For the equation (-1,2), $y=\frac{1}{2}x-3$, write an equation in slope intercept form for the line that passes through the given point and is parallel to the graph of the given equation.
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Step 1
Given point (-1,2) and the line $y=\frac{1}{2}x-3$
Step 2
We know that the slope of two parallel lines are equal.
The slope of the line $y=\frac{1}{2}x-3ism=\frac{1}{2}$
So, the slope of required line is also $m=\frac{1}{2}$. The equation of line is
$y-{y}_{1}=m\left(x-{x}_{1}\right)$
$y-2=\frac{1}{2}\left(x+1\right)$
$y-2=\frac{1}{2}x+\frac{1}{2}$
$y=\frac{1}{2}x+\frac{5}{2}$