For the equation (-1,2), y= \frac{1}{2}x - 3, write an equation in slope intercept form for the line that passes through the given point and is parallel to the graph of the given equation.

Annette Arroyo 2021-05-14 Answered
For the equation (-1,2), \(y= \frac{1}{2}x - 3\), write an equation in slope intercept form for the line that passes through the given point and is parallel to the graph of the given equation.

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Expert Answer

pattererX
Answered 2021-05-15 Author has 10748 answers
Step 1
Given point (-1,2) and the line \(y =\frac{1}{2}x-3\)
Step 2
We know that the slope of two parallel lines are equal.
The slope of the line \(y=\frac{1}{2}x-3 is m = \frac{1}{2}\)
So, the slope of required line is also \(m = \frac{1}{2}\). The equation of line is
\(y-y_{1}=m(x-x_{1})\)
\(y-2=\frac{1}{2}(x+1)\)
\(y-2=\frac{1}{2}x+\frac{1}{2}\)
\(y=\frac{1}{2}x+\frac{5}{2}\)
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