Compute the Inverse Laplace Transform of \(F(s) =\frac{s}{R^2s^2+16\pi^2}\)
take \(R=70\)
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Inverse Laplace transformation of (s^2 + s)/(s^2 +1)(s^2 + 2s + 2)
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\(L\left\{t-e^{-3t}\right\}\)
which of the laplace transform is
\(1.)\ L\left\{t-e^{-3t}\right\}=\frac{1}{s^{2}}+\frac{1}{s-3}\)
\(2.)\ L\left\{t-e^{-3t}\right\}=\frac{1}{s^{2}}-\frac{1}{s-3}\)
\(3.)\ L\left\{t-e^{-3t}\right\}=\frac{1}{s^{2}}+\frac{1}{s+3}\)
\(4.)\ L\left\{t-e^{-3t}\right\}=\frac{1}{s^{2}}-\frac{1}{s+3}\)
