Find the first partial derivatives of the following functions. g(x,y)=\cos^{5}(x^{2}y^{3})

Albarellak

Albarellak

Answered question

2021-03-26

Find the first partial derivatives of the following functions.
g(x,y)=cos5(x2y3)

Answer & Explanation

komunidadO

komunidadO

Skilled2021-03-28Added 86 answers

Step 1
To find the partial derivatives.
g(x,y)=cos5(x2y3)
Step 2
Let us first evaluate the partial derivative with respect to x.
We differentiate the function with respect to x keeping y constant.
g(x,y)x=5cos4(x2y3)(sin(x2y3))(2xy3) (Chain Rule of differentiation is also applicable)
=10xy3cos4(x2y3)sin(x2y3)
Step 3
Now, let us evaluate the partial derivative with respect to y.
We differentiate the function with respect to y keeping x constant.
g(x,y)y=5cos4(x2y3)(sin(x2y3))(3x2y2) (Chain Rule of differentiation is also applicable)
=15x2y2cos4(x2y3)sin(x2y3)

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?