Step 1

Given the system of equations

4x+2y=25

4x-y=-5

If value of y is 10 then we need to find the value of x.

Now,

If value of y is 10 then it must satisfy to both equations

By putting the value of y in equation first then we get

\(\displaystyle{4}{x}+{2}\times{10}={25}\)

4x+20=25

4x=25-20

4x=5

\(\displaystyle{x}={\frac{{{5}}}{{{4}}}}\)

x=1.25

Given the system of equations

4x+2y=25

4x-y=-5

If value of y is 10 then we need to find the value of x.

Now,

If value of y is 10 then it must satisfy to both equations

By putting the value of y in equation first then we get

\(\displaystyle{4}{x}+{2}\times{10}={25}\)

4x+20=25

4x=25-20

4x=5

\(\displaystyle{x}={\frac{{{5}}}{{{4}}}}\)

x=1.25