A system of linear equations is given below.2x+4y=10-\frac{1}{2}x+3=yFind the solution to the system of equations.A. (0, -3)B. (-6, 0)C.

Chaya Galloway 2021-03-10 Answered

A system of linear equations is given below.
2x+4y=10
12x+3=y
Find the solution to the system of equations.
A. (0, -3)
B. (-6, 0)
C. There are infinite solutions.
D. There are no solutions.

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Expert Answer

Daphne Broadhurst
Answered 2021-03-12 Author has 109 answers

Step 1
Given system of equations are:
2x+4y=10
12x+3=y
Solution:
We have equations:
2x+4y=10...(1)
12x+3=y
x+6=2y
x+2y=6...(2)
Step 2
We know that if:
a1a2=b1b2qc1c2 then two lines are parallel.
And when two lines are parallel then there is no solution.
We have, a1=2,b1=4,c1=10 and a2=1,b2=2,c2=6.
a1a2=21=2
b1b2=21=2
c1c2=106=53
We find that a1a2=b1b2qc1c2.
Step 3
Therefore, given two lines are parallel.
Therefore, there are no solutions.
Hence, option (D) is correct answer.

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