\(\displaystyle{x}\equiv{3}\pm{o}{d}{5}\)

\(\displaystyle{x}\equiv{7}\pm{o}{d}{8}\)

We see that the solution x is unique modulo 5.8=40.

Now, 8(2)-5(3)=1.

Thus,

x=3.8(2)-7.5(3)

x=48-105

x=-57

\(\displaystyle{x}=-{17}\pm{o}{d}{\left\lbrace{40}\right\rbrace}\)

\(\displaystyle{x}={23}\pm{o}{d}{\left\lbrace{40}\right\rbrace}\)

Therefore, x =23.

\(\displaystyle{x}\equiv{7}\pm{o}{d}{8}\)

We see that the solution x is unique modulo 5.8=40.

Now, 8(2)-5(3)=1.

Thus,

x=3.8(2)-7.5(3)

x=48-105

x=-57

\(\displaystyle{x}=-{17}\pm{o}{d}{\left\lbrace{40}\right\rbrace}\)

\(\displaystyle{x}={23}\pm{o}{d}{\left\lbrace{40}\right\rbrace}\)

Therefore, x =23.