Step 1

we have to factorise the polynomial.

\(\displaystyle{f{{\left({x}\right)}}}={9}{x}^{{{2}}}+{64}\)

Step 2

\(\displaystyle{f{{\left({x}\right)}}}={9}{x}^{{{2}}}+{64}\)

here f(x)>0

f(x) cannot be factored for real values of x.

therefore

\(\displaystyle{9}{x}^{{{2}}}+{64}\) is prime.

we have to factorise the polynomial.

\(\displaystyle{f{{\left({x}\right)}}}={9}{x}^{{{2}}}+{64}\)

Step 2

\(\displaystyle{f{{\left({x}\right)}}}={9}{x}^{{{2}}}+{64}\)

here f(x)>0

f(x) cannot be factored for real values of x.

therefore

\(\displaystyle{9}{x}^{{{2}}}+{64}\) is prime.