Solve the following equation. Indicate which of the values you find are allowed to be solutions to the original equation. \frac{-40}{x^{2}}+\frac{13}{x}=1

slaggingV

slaggingV

Answered question

2021-05-16

Solve the following equation. Indicate which of the values you find are allowed to be solutions to the original equation.
40x2+13x=1

Answer & Explanation

doplovif

doplovif

Skilled2021-05-18Added 71 answers

Step 1
We have to solve the given quadratic equation
Step 2
Given
40x2+13x=1
40+13xx2=1
40+13x=x2
x213x+40=0
x28x5x+40=0
x(x8)5(x8)=0
(x8)(x5)=0
x=5,8
Hence, solution of 40x2+13x=1 is x = 5,8

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