# Solve differential equation dy/(dt)+2y=1

Solve differential equation $dy/\left(dt\right)+2y=1$
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escumantsu

$dy/\left(dt\right)+Py=Q$
Hence P=2, Q=1
$I.F.={e}^{\int Pdt}$
$={e}^{\int 2dt}$
$={e}^{2t}$
$y\ast I.F.=\int Q\ast I.F.$
$y{e}^{2t}=\int 1\left({e}^{2t}\right)$
$y{e}^{2t}={e}^{2t}/2+C$
$y=1/2+C{e}^{-2t}$

Jeffrey Jordon