If A=begin{bmatrix}1 & 1 3 & 4 end{bmatrix} , B=begin{bmatrix}2 1 end{bmatrix} ,C=begin{bmatrix}-7 & 1 0 & 4 end{bmatrix},D=begin{bmatrix}3 & 2 & 1 en

vestirme4 2020-10-21 Answered
If A=[1134],B=[21],C=[7104],D=[321] and E=[234121]
Find , if possible,
a) A+B , C-A and D-E b)AB, BA , CA , AC , DA , DB , BD , EB , BE and AE c) 7C , -3D and KE
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Expert Answer

Yusuf Keller
Answered 2020-10-22 Author has 90 answers
Step 1
We can add and subtract matrices only which of them have same order.
For multiplication of two matrices it is necessary that no. of columns of first matrix must be equal to no of rows in second matrix.
Step 2
Here,
A=[1134],B=[21],C=[7104],D=[321] and E=[234121]
a) A+B , order of A is 2×2 order of B(2×1)
So, Not possible
C-A
CA=[7104][1134]=[71110344]=[8030]
CA=[8030]
D-E
D-E have different orders
So,not possible
b) AB
AB=[1134][21]=[2+16+4]=[310]
Hence
AB=[310]
BA here [B]2×1[A]2×2
number of columns of B number of row in A
So,not possible
CA
CA=[7104][1134]=[7+37+40+120+16]=[431216]
Hence
CA=[431216]
AC
AC=[1134][7104]=[71+4213+16]=[752119]
Hence,
AC=[752119]
DA
[D]1×3[A]2×2
Number columns in [D] number rows in [A]
So,not possible DB . Not possible BD. Not possible
EB.[E]2×3[B]2×1
Not possible
BE
[B]2×1[E]2×3
Not possible
AE
AE=[1134][234121]=
=[2+13+2416+49+8124]=[35310178]
Hence,
AE=[35310178]
(c)7C=7[7104]=[497028]
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Jeffrey Jordon
Answered 2022-01-29 Author has 2070 answers

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