A person stands in a stationary canoe and throws a 5.22 kgstone with a velocity of 8.20 m/s at an angle of 34.0 degrees abovethe horizontal. The perso

floymdiT 2021-04-15 Answered
A person stands in a stationary canoe and throws a 5.22 kgstone with a velocity of 8.20 m/s at an angle of 34.0 degrees abovethe horizontal. The person and the canoe have a combined massof 105 kg. Ignoring air resistance and effects of the water,find the horizontal recoil velocity (magnitude and direction) of the canoe.

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Expert Answer

Mayme
Answered 2021-04-17 Author has 9455 answers
Conservation of linear momentum:
\(\displaystyle{\left({m}_{{{1}}}+{m}_{{{2}}}\right)}{v}_{{{i}}}={m}_{{{1}}}{v}_{{{1}{f}}}+{m}_{{{2}}}{v}_{{{2}{f}}}\)
\(\displaystyle{0}={\left({5.22}\right)}{\left({8.2}\right)}{\cos{{34}}}+{105}{v}_{{{2}{f}}}\)
Solve for \(\displaystyle{v}_{{{2}{f}}}\). The answer will be negative,meaning the velocity of the canoe will be in the direction oppositethat of the stone.
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