A person stands in a stationary canoe and throws a 5.22 kgstone with a velocity of 8.20 m/s at an angle of 34.0 degrees abovethe horizontal. The perso

floymdiT

floymdiT

Answered question

2021-04-15

A person stands in a stationary canoe and throws a 5.22 kgstone with a velocity of 8.20 m/s at an angle of 34.0 degrees abovethe horizontal. The person and the canoe have a combined massof 105 kg. Ignoring air resistance and effects of the water,find the horizontal recoil velocity (magnitude and direction) of the canoe.

Answer & Explanation

Mayme

Mayme

Skilled2021-04-17Added 103 answers

Conservation of linear momentum:
(m1+m2)vi=m1v1f+m2v2f
0=(5.22)(8.2)cos34+105v2f
Solve for v2f. The answer will be negative,meaning the velocity of the canoe will be in the direction oppositethat of the stone.

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