A 60.0 kg runner expends 300 W of power whilerunning. 10% of the energy is delivered to the musclesand 90% of the energy is primarily removed from the body bysweating. Determine the volume of bodily fluid( assume it'swater) lost per hour. (at 37.0 Celcius, the latent heatof evaporation of water is 2.41×106 J/kg).

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A 60.0 kg runner expends 300 W of power whilerunning.   10% of the energy is delivered to the musclesand 90% of the energy is primarily removed from the body bysweating. Determine the volume of bodily fluid( assume it&#039;swater) lost per hour. (at 37.0 Celcius, the latent heatof evaporation of water is 2.41×106 J/kg).

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A 60.0 kg runner expends( P=300W) of power whilerunning. 10% of the energy is delivered to the musclesand 90% of the energy is primarily removed from the body bysweating. Here ; Power (P)=300W Time (t)=3600s The latent heat of evaporation of water ( Lv=2.41×106 J/kg). The energy dissipated by the person (E)=P⋅t =1.08⋅106J The energy primarily removed from the body bysweating Q=90% ( 1.08⋅106J) =9.72⋅105J The mass of bodily fluid( assume it&#039;s water) lost per hour. (at 37.0 Celcius),the latent heat ofevaporation of water is 2.41×106Jkg. m=Q/Lv =9.72⋅105J2.41×106Jkg =0.403kg The volume of bodily fluid( assume it&#039;s water) lost per hour. (at 37.0 Celcius, the latent heat ofevaporation of water is 2.41×106Jkg V=mrw =403cm3.

A 60.0 kg runner expends 300 W of power whilerunning. 10% of the energy is delivered to the musclesand 90% of the energy is primarily removed from the

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