A charge of 6.00\times10^{-9} C and a charge of -3.00\times10^{-9} C are separated by a distance of 60.0 cm. Find the position at which a third charge, of 12.0\times10^{-9} C, can be placed so that the net electrostatic force on it is zero.

Trent Carpenter

Trent Carpenter

Answered question

2021-05-03

A charge of 6.00×109 C and a charge of 3.00×109 C are separated by a distance of 60.0 cm. Find the position at which a third charge, of 12.0×109 C, can be placed so that the net electrostatic force on it is zero.

Answer & Explanation

Delorenzoz

Delorenzoz

Skilled2021-05-05Added 91 answers

Let q1=6.00×109 C
q2=3.00×109 C
The distance of seperation =60 cm
=0.6m
Let the position of the third charge q3 beat a distance (x) from the charge q2 now as the net electrostatic force on the charge q3 must be zero, the forces due to q1 and q2 on q3 must be equal in magnitude and oppsite, so that they will canceal each other and the netelectrostatic force is zero
then the force F1 on q3 due to q1 will be
F1=k(q1q3)(0.6+x)2
and the force F2 on q3 due to q2 will be
F1=k(q2q3)(x)2
as F1=F2
Solve for x

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