A 1200kg pick up truck traveling south at 15m/s collides witha 750kg car traveling east. The two vehicles stick together. Thefinal position of the wre

Carol Gates

Carol Gates

Answered question

2021-03-26

A 1200kg pick up truck traveling south at 15m/s collides witha 750kg car traveling east. The two vehicles stick together. Thefinal position of the wreckage after the collision is 25m, atan angle of 50 south of east, from the point of impact. If thecoefficient of friction between the tires and the road, from thelocation of the collision to the point at which the wreckage comesto rest is 0.4, what was the speed of the car just before thecollision?

Answer & Explanation

FieniChoonin

FieniChoonin

Skilled2021-03-28Added 102 answers

Final x position: 25m cos(50degrees) = 16.06969...m
Let v1ξ be initial velocity, vxf be velocity immediately after collision, and vx3 be resting velocity.
vx32=(0ms)2=vxf2+2a?x=vxf2+2(0.49.8ms2)16.06969 m
vxf=11.22 m/s
m1v1ξ+m2v2ξ=(m1+m2)vxf
(750kg)v1ξ+1200kg(0ms)=(750kg+1200kg)(11.2ms)
v1ξ=29.2ms
I may be wrong though

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?