A wind farm generator uses a two-bladed propellermounted on a pylon at a height of 20 m. The length of eachpropeller blade is 12 m. A tip of the prope

glamrockqueen7

glamrockqueen7

Answered question

2021-04-24


A wind farm generator uses a two-bladed propellermounted on a pylon at a height of 20 m. The length of eachpropeller blade is 12 m. A tip of the propeller breaks offwhen the propeller is vertical. The fragment flies offhorizontally, falls, and strikes the ground at P. Just beforethe fragment broke off, the propeller was turning uniformly, taking1.2 s for each rotation. In the above figure, the distancefrom the base of the pylon to the point where the fragment strikesthe ground is closest to:
a) 130 m
b) 160 m
c) 120 m
d) 140 m
e) 150 m

Answer & Explanation

okomgcae

okomgcae

Skilled2021-04-26Added 93 answers

To find the velocity of the propeller:
find the cricumference of the propeller blade:
πr2=π(122)=144π
if it travels this distance in 1.2 seconds:
v=144π1.2=120πms
The total height is 32 m, so use equation of motion todetermine the time of flight:
d = 32 m
a=9.8ms2
t = ?
Vi=0
d=Vt+12at2=2.55 seconds
now put this into Vo=xt and solve for x:
Vot=x=120π2.55=147.8m
so this would correspond to e).
Jeffrey Jordon

Jeffrey Jordon

Expert2021-10-07Added 2605 answers

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81m/s2 = a

r = Radius = 12 m

Time taken to fall

s=ut+12at2

0.809=0t+12×9.81×t2

t=(20+12)×29.81

t=2.554s

Speed is given by

v=rω

v=12×5.2

v=62.4 m/s

Distance is given by

s=vt

s=62.4×2.554

s=159.37 m

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