# A vertical cylinder of cross-sectional area 0.050m^2 is fitted with a tight-fitting, frictionless pistionof mass 5.0 kg. If there are 3.0 mol of ideal gas in the cylinderat 500 K, determine the height "h" at which the postion will be inequilibrium.

A vertical cylinder of cross-sectional area $$\displaystyle{0.050}{m}^{{2}}$$ is fitted with a tight-fitting, frictionless pistionof mass 5.0 kg. If there are 3.0 mol of ideal gas in the cylinderat 500 K, determine the height "h" at which the postion will be inequilibrium.

• Live experts 24/7
• Questions are typically answered in as fast as 30 minutes
• Personalized clear answers

### Plainmath recommends

• Get a detailed answer even on the hardest topics.
• Ask an expert for a step-by-step guidance to learn to do it yourself.

Asma Vang

A vertical cylinder ofcross-sectional area 0.050 $$\displaystyle{m}^{{2}}$$ is fitted with atight-fitting, frictionless pistion of mass 5.0 kg. If there are 3.0 mol of ideal gas in the cylinder at 500 K, determine the height"h" at which the postion will be in equilibrium.
the height "h" at which thepostion will be in equilibrium can be found by using $$\displaystyle{h}={\frac{{{V}}}{{{A}}}}$$
according to ideal gaslaw $$V=\frac{nRT}{P} n = 3.0 mol , T= 500 K , R = 8.31 J/ mol .K$$
Where $$\displaystyle{P}_{{{a}{t}{m}}}+{P}_{{{g}{a}{u}\ge}}$$
$$\displaystyle{P}_{{{a}{t}{m}}}={1.013}\cdot{10}^{{5}}$$ Pa
$$\displaystyle{P}_{{{g}{a}{u}\ge}}={\frac{{{F}}}{{{A}}}}$$
$$\displaystyle={\frac{{{m}{g}}}{{{A}}}}$$
where m is mass =5.0kg, $$\displaystyle{g}={9.8}\frac{{m}}{{s}^{{2}}}$$
A is area $$\displaystyle={0.050}{m}^{{2}}$$
plug the values in corresponding equations and calculatea for the answer