An electron enters a uniform magnetic field B= 0.23T at a 45 degree angle to B. Determine the pitch p (distance between loops) of the electron's helical path assuming its speed to be 3.0\cdot10^6 m/s.

Aneeka Hunt 2021-02-10 Answered
An electron enters a uniform magnetic field B= 0.23T at a 45 degree angle to B. Determine the pitch p (distance between loops) of the electron's helical path assuming its speed to be \(\displaystyle{3.0}\cdot{10}^{{6}}\) m/s.

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Expert Answer

saiyansruleA
Answered 2021-02-12 Author has 5001 answers
Given
magnetic field B = 0.23 T
angle \(\displaystyle\theta={45}\)
velocity \(\displaystyle{V}={3}\cdot{10}^{{6}}\) m/s
time period of revolution
\(\displaystyle{T}={\frac{{{2}\theta{m}}}{{{B}{q}}}}\)
mass of the electron \(\displaystyle{m}={9.1}\cdot{10}^{{-{31}}}\) kg
charge of the electron \(\displaystyle{q}={1.6}\cdot{10}^{{-{16}}}\) C
\(\displaystyle\text{pitch of the helix}=\text{time period}\cdot\text{velocity(parallel)}\)
\(\displaystyle{V}_{{{p}{a}{r}{a}{l}\le{l}}}={V}\cdot{\cos{{45}}}\)
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