A 10 kg object experiences a horizontal force which causes it to accelerate at 5 \(\displaystyle\frac{{m}}{{s}^{{2}}}\), moving it a distance of 20 m, horizontally. How much work is done by the force?

The magnitude of the force is given by

\(\displaystyle{F}={m}{a}={\left({10}\right)}{\left({5}\right)}={50}{N}\)

It acts over a distance of 20 m, in the same direction as the displacement of the object, implying that the total work done by the force is given by

\(\displaystyle{W}={F}{x}={\left({50}\right)}{\left({20}\right)}={1000}\) Joules

The magnitude of the force is given by

\(\displaystyle{F}={m}{a}={\left({10}\right)}{\left({5}\right)}={50}{N}\)

It acts over a distance of 20 m, in the same direction as the displacement of the object, implying that the total work done by the force is given by

\(\displaystyle{W}={F}{x}={\left({50}\right)}{\left({20}\right)}={1000}\) Joules