 A 10 kg objectexperiences a horizontal force which causes it to accelerate at 5 m/s^2, moving it a distance of 20 m, horizontally.How much work is don Haven 2021-02-19 Answered
A 10 kg objectexperiences a horizontal force which causes it to accelerate at 5 $$\displaystyle\frac{{m}}{{s}^{{2}}}$$, moving it a distance of 20 m, horizontally.How much work is done by the force?
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A 10 kg object experiences a horizontal force which causes it to accelerate at 5 $$\displaystyle\frac{{m}}{{s}^{{2}}}$$, moving it a distance of 20 m, horizontally. How much work is done by the force?
The magnitude of the force is given by
$$\displaystyle{F}={m}{a}={\left({10}\right)}{\left({5}\right)}={50}{N}$$
It acts over a distance of 20 m, in the same direction as the displacement of the object, implying that the total work done by the force is given by
$$\displaystyle{W}={F}{x}={\left({50}\right)}{\left({20}\right)}={1000}$$ Joules