A fish is swimming in water inside a thin spherical glass bowlof uniform thickness. Assuming the radius of curvature of thebowl is 25cm, locate the image of the fish if the fish is located:(a) at the center of the bowl; (b) 20.0 cm from the side of the bowl between the observer andthe center of the bowl.

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A fish is swimming in water inside a thin spherical glass bowlof uniform thickness. Assuming the radius of curvature of thebowl is 25cm, locate the image of the fish if the fish is located:(a) at the center of the bowl;  (b) 20.0 cm from the side of the bowl between the observer andthe center of the bowl.

Faiza Fuller · Accepted Answer

Lnw=1.33, na=1 are the refreactive indices of water and air respectively. When fish is at the center of bowl, nwp+naq=na−nwR p is object q is image of fish and R is radius of curvature 1.3312.5+1q=1−1.33−12.5 1q=.3312.5−1.3312.5=−112.5 q=12.5 ie at the center itself when fish is at 20 cm 1.3320+1q=1−1.33−12.5 1q=.3312.5−1.3320 q=24.9376cm In this problem because glass is thin we neglect glassref index and take only water ref index and tha of air

A fish is swimming in water inside a thin spherical glass bowlof uniform thickness. Assuming the radius of curvature of thebowl is 25cm, locate the im

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