A dead battery is charged by connecting it to the live battery ofanother car with jumper cables. Assume that V=9.5 V and R=0.90 Ohms. Determine the current in the starter. Your answer differs from the correct answerby orders of magnitude. A Determine the current in the dead battery. Your answer differs from the correct answerby orders of magnitude.

A dead battery is charged by connecting it to the live battery ofanother car with jumper cables. Assume that V=9.5 V and R=0.90 Ohms. Determine the current in the starter. Your answer differs from the correct answerby orders of magnitude. A Determine the current in the dead battery. Your answer differs from the correct answerby orders of magnitude.

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asked 2021-04-02
A dead battery is charged by connecting it to the live battery ofanother car with jumper cables. Assume that V=9.5 V and R=0.90 Ohms.
Determine the current in the starter.
Your answer differs from the correct answerby orders of magnitude. A
Determine the current in the dead battery.
Your answer differs from the correct answerby orders of magnitude.

Answers (1)

2021-04-04
Assume current through starter be Is flowing downwards
Assume current through Dead battery be Id flowing downwards
So current through live battery is (\(\displaystyle{I}_{{s}}+{I}_{{d}}\)) flowing upwards
KVL for left loop -
\(\displaystyle+{9.5}{V}+{\left({0.9}\ {O}{h}{m}{s}\right)}{l}{d}-{\left({0.06}\ {O}{h}{m}{s}\right)}{l}{s}={0}\)
KVL for the big loop
\(\displaystyle+{12}{V}-{\left({0.01}\ {O}{h}{m}{s}\right)}{\left({l}{s}+{l}{d}\right)}-{\left({0.06}\ {O}{h}{m}{s}\right)}{l}{s}={0}\)
Solving these teo equation, we get
\(\displaystyle{l}_{{s}}={0.865}\ {A}\)
\(\displaystyle{l}_{{d}}={171.305}\ {A}\)
0

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