On a clear day the electric field in the atmosphere near theearth's surface is 100 N/C, directed vertically downward. If we adopt the convention that the potential at the earth'ssurface is 0, what is the potential 100 m above the surface?

Jason Farmer

Jason Farmer

Answered question

2021-04-06

On a clear day the electric field in the atmosphere near theearths

Answer & Explanation

Liyana Mansell

Liyana Mansell

Skilled2021-04-08Added 97 answers

Given E = 100 N/C = 100 V/m downward;
Vearths surface=0;?y=100m.
Dirction of the E at any point is the direction in which afree positive charge tendsto move, this also down the pot gradient.So, E is downward means, a lower point is at a lower pot.and a higher point is at a higher potential.
The relation between E and change in pot,?V is given by the eqn,
E = - ?V/?y in onedimension.
Therefore, ?V = -E.?y = --100x100 = +10000 V = +10 kV.
(E is -ve as we up; y is +ve).
Or as explained earlier, pot is higher at higherpoints.
Therefore, the pot at the given point P, 100 mabove earths

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