When a 75 g mass is suspended from a vertical spring, the spring isstretched from a length of 4.0 cm to a length of 7.0 cm. If themass is then pulled downward an additional 10 cm, what is the totalwork done against the spring force in joules?

Reggie

Reggie

Answered question

2021-03-24

When a 75 g mass is suspended from a vertical spring, the spring isstretched from a length of 4.0 cm to a length of 7.0 cm. If themass is then pulled downward an additional 10 cm, what is the totalwork done against the spring force in joules?

Answer & Explanation

Obiajulu

Obiajulu

Skilled2021-03-26Added 98 answers

Given Data :- Intial length of the spring (l1)=4cm=0.04m.
Final length of the spring (l2)=7cm.=0.07m.
elongationof the wire (e)=l2l1=0.070.04=0.03m.
mass attached to the spring (m) =75g.=0.075kg.
Acceleration due to gravity (g)=9.8ms2
Therefore Force constant K=mge
K=0.075×9.80.03
K=24.5Nm
W=12Kx2
Work Done in streched spring.
where x = streched length =10cm.= 0.1m.
W=12×24.5×(0.1)2
W=0.1225J.

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