A 2.00 kg ball is attached to a ceiling by a 0.76 m longstring. The height of the room is 3.18 m. What is the gravitationalpotential energy associated with the ball relative to (a) theceiling ? (b) the floor? (c) a point at the same elevation as theball?

Marvin Mccormick

Marvin Mccormick

Answered question

2021-03-25

A 2.00 kg ball is attached to a ceiling by a 0.76 m longstring. The height of the room is 3.18 m. What is the gravitationalpotential energy associated with the ball relative to (a) theceiling ? (b) the floor? (c) a point at the same elevation as theball?

Answer & Explanation

stuth1

stuth1

Skilled2021-03-27Added 97 answers

The gravitational potential energy is given by
U = mgh
a) If we are measureing the amount of gravitational potentialenergy relative to the ceiling, then the ceiling is the point atwhich the potential energy is zero. The ball is hung .76 m below the ceiling, so its gravitational potential energy is
U=mgh=(2kg)(9.8ms2)(0.76m)=14.9J
This quantity is negative because it has less potentilenergy than that of an object of the same mass and situated at theheight of the ceiling.
b) The ceiling is 3.18 m high, so the balls

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