Car 1 has a mass of m1 = 65 ❝ 103 kg and moves at a velocity of v01 = +0.81 m/s. Car 2, with a mass of m2 = 92 ❝ 103 kg and a velocity of v02 = +1.2 m
Wribreeminsl
Answered question
2021-04-21
Car 1 weighs 65 103 kg and travels at a speed of v01 = +0.81 m/s. Car 2 passes car 1 and couples to it at a speed of v02 = +1.2 m/s and mass of m2 = 92 103 kg. In your response, ignore the effects of friction.
(a) Determine the velocity of their center of mass before the collision m/s
(b) Determine the velocity of their center of mass after the collision m/s
(c) Should your answer in part (b) be less than, greater than, or equal to the common velocity vf of the two coupled cars after the collision? less than greater than equal to
Answer & Explanation
yunitsiL
Skilled2021-04-23Added 108 answers
(a)
(b)The momentum of the system remains conserved.
The coupled boxcars move with same velocity V.
As the two boxcars are coupled, the velocity of center of mass Vcm =V=1.0385 m/s
(c)The momentum remains conserved in perfectly INELASTIC collision
As no external force has acted,the velocity of center of mass will not change.
Vcm before collision IS EQUAL TO Vcm after the collision
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