# A quarterback claims that he can throw the football ahorizontal distance of 183 m (200 yd). Furthermore, he claims thathe can do this by launching the

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For horizontal range of a projectile $$\displaystyle{R}={{V}_{{{0}}}^{{{2}}}}\frac{{\sin{{20}}}}{{g}}$$ Hence $$\displaystyle{V}{0}=\sqrt{{{R}\cdot\frac{{g}}{{\sin{{20}}}}}}=\sqrt{{{183}\cdot\frac{{9.8}}{{\sin{{60}}}}}}={45.5}\frac{{m}}{{s}}$$