The plane of a rectangular coil, 5.0-cm by 8.0-cm, is perpendicular to the direction of a magnetic field "B". If the coil has 75 turns and a total resistance of 8.0 Ohms, at what rate must the magnitude of "B" change to induce a current of 0.10 amps in the windings of the coil?

Clifland

Clifland

Answered question

2021-02-14

The plane of a rectangular coil, 5.0-cm by 8.0-cm, is perpendicular to the direction of a magnetic field "B". If the coil has 75 turns and a total resistance of 8.0 Ohms, at what rate must the magnitude of "B" change to induce a current of 0.10 amps in the windings of the coil?

Answer & Explanation

firmablogF

firmablogF

Skilled2021-02-16Added 92 answers

Area of the Reconciliation Circle = A
A=5cm×8cm=4010000=0.004m2
Suppose that the magnetic field's rate of change is: d B / dt =?
current = I = 0.1 A
resitence = R = 8 ohms
Consequently, the amount of induced emf would be
e=IR=0.1×8=0.8 volt
No. of turns of the coil = N = 75 turns
It is recognized by the equation for
Induced emf is :
e = A N dB / dt
thus, d B / dt = e / N A
=0.875×0.004
= 0.8 / 0. 3
= 2.7 T /s (2.666666667)

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