A uniform 8.40kg, spherical shell 50.0cm in diameter has foursmall 2.00kg masses attached to its outer surface and equallyspaced around it. This combi

Tabansi

Tabansi

Answered question

2021-02-19

A uniform 8.40kg, spherical shell 50.0cm in diameter has foursmall 2.00kg masses attached to its outer surface and equallyspaced around it. This combination is spinning about an axisrunning through the center of the sphere and two of the smallmasses. What friction torque is needed to reduce its angular speedfrom 75.0rpm to 50.0rpm in 30.0s?

Answer & Explanation

tafzijdeq

tafzijdeq

Skilled2021-02-21Added 92 answers

The moment of inertia of the whole system is
I=(25)MR2+4(12)mR2
M = 8.4kg
m =2kg
R = 0.5m
I=0.6kgm2
The initial and final angular speeds are
ω0=75r±=7.84rads
ω=50r±=5.236rads
using the equation
(ωω0)=αt
α=0.08726rads2
the torque is
T=Iα=0.0524Nm

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