A force of 250 N is applied to a hydraulic jack piston that is0.01 m in diameter. If the piston which supports the load hasa diameter of 0.10 m, approximately how much mass can belifted. Ignore any difference in height between thepistons.

Khadija Wells

Khadija Wells

Answered question

2021-04-24

A force of 250 N is applied to a hydraulic jack piston that is0.01 m in diameter. If the piston which supports the load hasa diameter of 0.10 m, approximately how much mass can belifted. Ignore any difference in height between thepistons.

Answer & Explanation

yagombyeR

yagombyeR

Skilled2021-04-26Added 92 answers

P1 = P2 
F1/A1 =F2/A2 
F1πr12=F2πr22 
When you solve for  F2 and can cancel the "pi"s on both sides, you have:
F2=F1(r2r1)2, remember diameter = 2 * radius... the force you obtain (f2) represents the maximum weight that can be lift

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