A thin piece if wire 4.00mm long is located in a plpaneperpendicular to the optical axis and 60.0cm in front of a thinlens. The sharp image of the wire formed on a screen is 2.0mm long.What is the focal length of the lens?

DofotheroU

DofotheroU

Answered question

2021-04-26

A thin piece if wire 4.00mm long is located in a plpaneperpendicular to the optical axis and 60.0cm in front of a thinlens. The sharp image of the wire formed on a screen is 2.0mm long.What is the focal length of the lens?

Answer & Explanation

Jaylen Fountain

Jaylen Fountain

Skilled2021-04-28Added 169 answers

The object distance u = 60cm
height of the real, inverted image hi=2mm
height of object h0=4mm
Thus, the magnification M=hih0=vu
- 2 / 4 = - v / 60
calculating we get v = 30cm
The focal lenghtof the lens is calculated using
1 / f = 1 / u + 1 / v
= 1 / 60 + 1 / 30
Thus, f = 20cms

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?