A 2.00-m-long air column is open at both ends. Thefrequency of a certain harmonic is 410 Hz, and the frequency of thenext-higher harmonic is 492 Hz. Determine the speed of soundin the air column.

babeeb0oL

babeeb0oL

Answered question

2021-03-24

A 2.00-m-long air column is open at both ends. Thefrequency of a certain harmonic is 410 Hz, and the frequency of thenext-higher harmonic is 492 Hz. Determine the speed of soundin the air column.

Answer & Explanation

SchulzD

SchulzD

Skilled2021-03-26Added 83 answers

For the fundamental ferquency, thewave length is twice the length of the pipe and hence
f1=v2L This is the first harmonic
let its frequency be = 410 Hz
let the frequency of the second (higher) harmonic be =492 Hz
so we can write
f1=410Hz
f2=492Hz
we have given l = 2.00 m
from the relation f2=vl=2f1 can calculate
velocity of the sound

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