1. S1 and S2, shown above, are thin parallel slits in an opaqueplate. A plane wave of wavelength λ is incident from the leftmoving in a direction perpendicular to the plate. On a screenfar from the slits there are maximums and minimums in intensity atvarious angles measured from the center line. As the angle isincreased from zero, the first minimum occurs at 3 degrees. Thenext minimum occurs at an angle of- A. 4.5 degrees B. 6 degrees C. 7.5 degrees D. 9 degrees E. 12 degrees

1. S1 and S2, shown above, are thin parallel slits in an opaqueplate. A plane wave of wavelength λ is incident from the leftmoving in a direction perpendicular to the plate. On a screenfar from the slits there are maximums and minimums in intensity atvarious angles measured from the center line. As the angle isincreased from zero, the first minimum occurs at 3 degrees. Thenext minimum occurs at an angle of- A. 4.5 degrees B. 6 degrees C. 7.5 degrees D. 9 degrees E. 12 degrees

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asked 2021-05-18
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1. S1 and S2, shown above, are thin parallel slits in an opaqueplate. A plane wave of wavelength λ is incident from the leftmoving in a direction perpendicular to the plate. On a screenfar from the slits there are maximums and minimums in intensity atvarious angles measured from the center line. As the angle isincreased from zero, the first minimum occurs at 3 degrees. Thenext minimum occurs at an angle of-
A. 4.5 degrees
B. 6 degrees
C. 7.5 degrees
D. 9 degrees
E. 12 degrees

Answers (1)

2021-05-20
6 degrees
\(\displaystyle{d}{\sin{{0}}}={m}\lambda\)
\(\displaystyle{{\sin{{3}}}^{{\circ}}=}{\left({1}\right)}{\left(\frac{\lambda}{{d}}\right)}\)
\(\displaystyle{\left(\frac{\lambda}{{d}}\right)}={.052}\)
When m=2,
\(\displaystyle{\sin{{0}}}={.105}\) therefore theta is 6 degrees.
0

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