6 degrees

\(\displaystyle{d}{\sin{{0}}}={m}\lambda\)

\(\displaystyle{{\sin{{3}}}^{{\circ}}=}{\left({1}\right)}{\left(\frac{\lambda}{{d}}\right)}\)

\(\displaystyle{\left(\frac{\lambda}{{d}}\right)}={.052}\)

When m=2,

\(\displaystyle{\sin{{0}}}={.105}\) therefore theta is 6 degrees.

\(\displaystyle{d}{\sin{{0}}}={m}\lambda\)

\(\displaystyle{{\sin{{3}}}^{{\circ}}=}{\left({1}\right)}{\left(\frac{\lambda}{{d}}\right)}\)

\(\displaystyle{\left(\frac{\lambda}{{d}}\right)}={.052}\)

When m=2,

\(\displaystyle{\sin{{0}}}={.105}\) therefore theta is 6 degrees.