Answered: "What is the potential difference between yi=−5 cm..."

Nannie Mack

Answered question

2021-03-23

What is the potential difference between

y_{i} = - 5

cm and

y_{f} = 5

cm in the iniform electric field

\vec{E} = (20, 000 \hat{i} - 50, 000 \hat{j}) \frac{V}{m}

Jaylen Fountain

Skilled2021-03-25Added 169 answers

The electric field intensity is given by

\vec{E} = (20, 000 \hat{i} - 50, 000 \hat{j}) \frac{V}{m}

.
The electric field is the negative gradient of the potential V
i.e.

\vec{E} = - [\frac{δ V}{δ n} \hat{i} + \frac{δ V}{δ n} \hat{j} + \frac{δ V}{δ n} \hat{k}]

Thus,

V = - \int [E_{x} d x + E_{y} d y + E_{z} d z]

The given points are [0,-0.05] and [0,0.05] where the electric field intensity
is to be calculated
Let the potential at these points be

V_{i}

and

V_{f}

Then

V_{i} = - [- 50000 \times (- .05)] = - 2500 V

V_{f} = - [50000 \times .05] = 2500 V

Thus,

V_{f} - V_{i} = 2500 - (- 2500) = 5000 V

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