1) thework done by the 70 N force is

\(\displaystyle{W}_{{1}}={F}{d}{\cos{\theta}}={70}\cdot{5}{\cos{{20}}}={328.89}\ {J}\)

2) The normal force is perpendicular to the displacement ofthe motion, so it does no work.

\(\displaystyle{W}_{{2}}={0}\)

3) The gravitational force is perpendicular to the displacement, or the displacement in the vertical direction is 0.so the work done is 0

\(\displaystyle{W}_{{1}}={F}{d}{\cos{\theta}}={70}\cdot{5}{\cos{{20}}}={328.89}\ {J}\)

2) The normal force is perpendicular to the displacement ofthe motion, so it does no work.

\(\displaystyle{W}_{{2}}={0}\)

3) The gravitational force is perpendicular to the displacement, or the displacement in the vertical direction is 0.so the work done is 0