# Suppose unpolarized light of intensity 150 W/m^{2} falls on the polarizer at an angle 30. What is the light intensity reaching the photocell?

Caelan 2021-04-02 Answered
Suppose unpolarized light of intensity $150\frac{W}{{m}^{2}}$ falls on the polarizer at an angle 30. What is the light intensity reaching the photocell?
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## Expert Answer

timbalemX
Answered 2021-04-04 Author has 108 answers
Intensity of unpolarised light $I=150\frac{W}{{m}^{2}}$
Angle = 30 degrees
Intensity reaching the photocell ${I}^{\prime }=\frac{I}{2}=75\frac{W}{{m}^{2}}$
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