Caelan
2021-04-02
Answered

Suppose unpolarized light of intensity $150\frac{W}{{m}^{2}}$ falls on the polarizer at an angle 30. What is the light intensity reaching the photocell?

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timbalemX

Answered 2021-04-04
Author has **108** answers

Intensity of unpolarised light $I=150\frac{W}{{m}^{2}}$

Angle = 30 degrees

Intensity reaching the photocell$I}^{\prime}=\frac{I}{2}=75\frac{W}{{m}^{2}$

Angle = 30 degrees

Intensity reaching the photocell

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