Suppose electrons enter the uniform electric field midwaybetween two plates, moving at an upward 45 degree angle as shown.What maximum speed can the e

facas9 2021-05-02 Answered

Suppose electrons enter the uniform electric field midwaybetween two plates, moving at an upward 45 degree angle as shown.What maximum speed can the electrons have if they are to avoidstriking the upper plate. Ignore fringing of the field. Upper plate is negatively charged bottom plate is positivelycharged length of plate is 6cm and distance from top of top plateto bottom of bottom plate is 1cm.

E = 5.0 \times 10^{3} \frac{N}{C}

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likvau

Answered 2021-05-04 Author has 75 answers

The vertical acceleration

a_{y} = \frac{- q E}{m} = \frac{- (1.6 \cdot 10^{- 19}) (5 \cdot 10^{3})}{9.11 \cdot 10^{- 31} k g}

= - 8.78 \cdot 10^{44} \frac{m}{\sec}

The vertical velocity is

V_{y}^{2} = V_{o y}^{2} + 2 a_{y} h

V_{o} \sin 45 = 0 + \sqrt{- 2 a_{y} h}

V_{o} = \frac{{[- (- 8.78 \cdot 10^{14} \frac{m}{s^{2}}) (0.010 m)]}^{\frac{1}{2}}}{\sin 45}

= 4.2 \cdot 10^{6} \frac{m}{s}

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