The ksp value of radium sulfate RaSO_{4} is 4.2\times 10^{-11}. If 25 mg of radium sulfate is placed in1.00x102mL of water, does all of it dissolve? if not howmuch dissolves?

shadsiei

shadsiei

Answered question

2021-04-06

The ksp value of radium sulfate RaSO4 is 4.2×1011. If 25 mg of radium sulfate is placed in1.00x102mL of water, does all of it dissolve? if not howmuch dissolves?

Answer & Explanation

delilnaT

delilnaT

Skilled2021-04-08Added 94 answers

KspofRaSO4=[Ra2+][SO42]
Ksp=s2
4.2×1011=s2
s=6.48106M
This is the solubility of radium sulfate
Now we have to calculate the molarity of the givenamount of RaSO4
Moles of solute = mass(g) / molarmass(g/mol)
molarity(M) = moles of solute/V(L)
We know 1000mg = 1g and 1000ml = 1L
So find this value and compare with s(where s is themolar solubility) , if it is less than s then it does notdissolve, if its more than the value s then it dissolves to aextent and if equal the value then all dissolves.

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