In an industrial cooling process, water is circulated through a system. If the water is pumped with a speed of 0.45 m/s under a pressure of 400 torr from the first floor through a 6.0-cm diameter pipe, what will be the pressure on the next floor 4.0 m above in a pipe with a diameter of 2.0 cm?

Cem Hayes 2021-02-18 Answered
In an industrial cooling process, water is circulated through a system. If the water is pumped with a speed of 0.45 m/s under a pressure of 400 torr from the first floor through a 6.0-cm diameter pipe, what will be the pressure on the next floor 4.0 m above in a pipe with a diameter of 2.0 cm?
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broliY
Answered 2021-02-20 Author has 97 answers
In an industrial cooling process, water is circulated through a system.
If the water is pumped with a speed of(v1=0.45ms)
under a pressure of (P1 = 400 torr) from the first floor througha(D1 = 6.0cm) diameter pipe,
Let 'P2' be the pressure on the next floor ( h = 4.0 m ) above in a pipe with adiameter of (D2 = 2.0 cm)
Density of water = 1000kgm3
From the equation of continuity we have
The rate is A1v1=A2v2
Or, v2=A1v1A2
Or, v2=(D1D2)2v1
Apply; Bernoulli's Theorem
P1+(12)v12+0=P2+(12)v22+hg
Put the above given values in the above expression , to get'P2'
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