A circular bar AB with ends fixed against rotation has a hole extending for half its length the outter diameter of the bar is d_2=100mm and the diamet

Reeves

Reeves

Answered question

2021-02-26

A circular bar AB with ends fixed against rotation has a hole extending for half its length the outter diameter of the bar is d2=100mm and the diameter of the hole is d1=80mm. L=1250mm.
At what distance x from the left hand end of the bar should a torque To be applied so that the reactive torques at thesupports be equal.

Answer & Explanation

escumantsu

escumantsu

Skilled2021-02-28Added 98 answers

Reactive tirque in A&B are equal
Ta=Tb
Ta×x=Tb×(1250x)
x=1250x

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?