A golf ball lies 2.00 m directly south of the hole on a levelgreen. On the first putt, the ball travels 3.00 m along astraight-line path at an angle of 5 degrees east of north; on thesecond putt, it travels a straight-line distance of 1.20 m at anangle of 6 degrees south of west. What would be the displacement ofa third putt that would put the ball in the hole? The answer in the back of the book is 1.3 m at 43 degreessouth of east. How do I get that?

Question

A golf ball lies 2.00 m directly south of the hole on a levelgreen. On the first putt, the ball travels 3.00 m along astraight-line path at an angle of 5 degrees east of north; on thesecond putt, it travels a straight-line distance of 1.20 m at anangle of 6 degrees south of west.   What would be the displacement ofa third putt that would put the ball in the hole?  The answer in the back of the book is 1.3 m at 43 degreessouth of east. How do I get that?

cheekabooy · Accepted Answer

Add the vector components of the putts: On the firstputt x1= 3 m * sin⁡(5)= .26m and y1 = 3m * cos⁡(5) = 2.989 m on the second putt x2 = 1.2 m *cos⁡(186) = -1.19 m and y2 = 1.2 m * sin⁡(186) = -1.25 m The resulting components are X = -.93 m and Y = 2.864 m Since the hole originally was at 2 m N the Y component of theball from the hole is .864 m So the resultant distance to the hole - (−.932+.8642)12=1.27m Also, the ball is .93 m W of the hole and .864 m N of the holeand tan = .864 / .93 and = 42.9 deg

A golf ball lies 2.00 m directly south of the hole on a levelgreen. On the first putt, the ball travels 3.00 m along astraight-line path at an angle o

Answered question

Answer & Explanation

New Questions in Other