A beaker of water sits in the sun until it reaches an equilibriumtemperature of 30C. The beaker is made of 100g of aluminum andcontains 180g of water.

BenoguigoliB

BenoguigoliB

Answered question

2021-03-27

A beaker of water sits in the sun until it reaches an equilibriumtemperature of 30C. The beaker is made of 100g of aluminum andcontains 180g of water. In an attempt to cool this system, 100g ofice at 0 celsius is added to the water.
A. Determine the final temperature of thesystem. Tf = 0 celsius, determine how much ice remains.
B. Repeat your calculations for 50g of ice.

Answer & Explanation

tabuordy

tabuordy

Skilled2021-03-29Added 90 answers

mass (mw) of water = 0.180kg
mass (mc) of cup madeof aluminium = 0.100 kg
specific heat (cw) of water =4186 JkgC
specific heat (ca) of aluminium= 9000 JkgC
temperature T=30C
first we calculate the energy required that meansthe energy that must be absorbed to cool the water and cup to 0C using theformula
Q=msT
=(mwcw+mcca)T
=.......J
(a)
if L is the latent heat of fusion of water thenat 0oC the amount of ice that must melt to absorb energy which is equal to Q will be
m=Q/L
=......gm
which will be less that 100 gm, so the finaltemperature will be remaining as 100oC with leftover ice
(b)
if 50 gm which is less than m is used, then itwill be melted all, then according to the law of conservation of energy we canwrite
mice=(L+cw(Tf0C))=(mwcw+mcca)(30CTf)

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