Assume that a ball of charged particles has a uniformly distributednegative charge density except for a narrow radial tunnel throughits center, from the surface on one side to the surface on the opposite side. Also assume that we can position a proton any where along the tunnel or outside the ball. Let FR be the magnitude of the electrostatic force on the proton when it islocated at the ball's surface, at radius R. As a multiple ofR, how far from the surface is there a point where the forcemagnitude is 0.44FR if we move the proton(a) away from the ball and (b) into the tunnel?

Question

Assume that a ball of charged particles has a uniformly distributednegative charge density except for a narrow radial tunnel throughits center, from the surface on one side to the surface on the opposite side. Also assume that we can position a proton any where along the tunnel or outside the ball. Let FR be the magnitude of the electrostatic force on the proton when it islocated at the ball&#039;s surface, at radius R. As a multiple ofR, how far from the surface is there a point where the forcemagnitude is 0.44FR if we move the proton(a) away from the ball and (b) into the tunnel?

yagombyeR · Accepted Answer

You can solve this problem by Gauss

Jeffrey Jordon · Accepted Answer

a) The flux is still&amp;nbsp;−750Nm2/C2&amp;nbsp;, as it is solely based on the contained charge.&amp;nbsp;b)&amp;nbsp;Use&amp;nbsp;ϕ=qϵ0​&amp;nbsp;to obtain the charge&amp;nbsp;q&amp;nbsp;:q=ϵ0ϕ=(8.85×10−12C2/N&amp;nbsp;m2)(−750&amp;nbsp;N.m2/C2)=−6.64×10−9CAnswer is&amp;nbsp;−6.64×10−9C

Assume that a ball of charged particles has a uniformly distributednegative charge density except for a narrow radial tunnel throughits center, from t

Answered question

Answer & Explanation

New Questions in Other