A uniform door (0.81m wide and 2.1m hight) weighs 140N and ishung on two hinges that fasten the long left side of the door to averticle wall. The hing

Tahmid Knox

Tahmid Knox

Answered question

2021-05-01

A uniform door (0.81m wide and 2.1m hight) weighs 140N and ishung on two hinges that fasten the long left side of the door to averticle wall. The hinges are 2.1m apart. Assume that thelower hinge bears all the weight of the door. Find themagnitude and direction of the horizontal component of the forceapplied to the door by (a) the upper hinge and (b) the lowerhinge. Determine the magnitude and direction of the forceapplied by the door to (c) the upper hinge and (d)the lower hinge.

Answer & Explanation

SabadisO

SabadisO

Skilled2021-05-03Added 108 answers

Equation 1: Fx = Lx - Ux, Lx =Ux
Equation 2: Fy = Ly - W = 0, Ly = W = 140 N
Equation 3: Torque = -W(d/2) + UxH = 0
Solution:
a) use equation 3
Ux = (Wd)/(2h) = 27 N to the left
b) equation 1, L = 27 N to the right
c) Newtons

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