A person is working near the secondary of a transformer. The primary voltage is 120 V at 60 Hz. The capacitance Cs, which is the stray capacitance between the hand and the secondary winding, is 20.0pF. Assuming the persom has a body resistance to grond of Rb=50 kOhms, deteremine the rms voltage across the body.

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The capacitive reactanceXc=12πfC&amp;nbsp;f is the frequency of the AC source, and C is the capacitance of the capacitor.&amp;nbsp;Substitute 20pG for C, and 60Hz for f&amp;nbsp;Xc=12πfC&amp;nbsp;=12π(60Hz)(20pF)(10−12F1pF)&amp;nbsp;=1.33×108&amp;nbsp;The impedance of the circuitRb2+(XC)2&amp;nbsp;Rb&amp;nbsp;is the body resistance of the person.&amp;nbsp;Substitute&amp;nbsp;50×103&amp;nbsp;Ohms for&amp;nbsp;Rb, and&amp;nbsp;1.33×108&amp;nbsp;Ohms for&amp;nbsp;Xc&amp;nbsp;Z=Rb2+(XC)2&amp;nbsp;=(50×103)2+(1.33×108)&amp;nbsp;=1.33×108&amp;nbsp;Ohms&amp;nbsp;The rms current in the circuit is,&amp;nbsp;Irms=△VrmsZ&amp;nbsp;△Vrms&amp;nbsp;is the rms voltage in the circuit.&amp;nbsp;Substitute 5000V for&amp;nbsp;△Vrms, and&amp;nbsp;1.33×108&amp;nbsp;for Z&amp;nbsp;=5000&amp;nbsp;V1.33×108&amp;nbsp;=3.76×10−5&amp;nbsp;A&amp;nbsp;The rms voltage across the body△Vb=IrmsRb&amp;nbsp;Substitute&amp;nbsp;3.76×10−5&amp;nbsp;A&amp;nbsp;for&amp;nbsp;Irms, and&amp;nbsp;50×103&amp;nbsp;for&amp;nbsp;Rb&amp;nbsp;△Vb=IrmsRb&amp;nbsp;=(3.76×10−5&amp;nbsp;A)(50×103)&amp;nbsp;=1.88V&amp;nbsp;&amp;nbsp;The rms voltage across the body is&amp;nbsp;1.88V

A person is working near the secondary of a transformer. The primary voltage is 120 V at 60 Hz. The capacitance C_s, which is the stray capacitance be

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