A pair of speakers separated by .700 m are driven by the sameoscillator at a frequency of 690 Hz. An observer originallypositioned at one of the speak

midtlinjeg

midtlinjeg

Answered question

2021-05-09

Generator drives two speakers with a distance between them of 0.700 m at a frequency of 690 Hz. Starting at one of the speakers, the observer moves down a path perpendicular to the line connecting the speakers.
How far must the observer move before the intensity reaches a relative maximum?
b. How far away from the speaker will the observer be when the first relative minimum in intensity is noticed?

Answer & Explanation

Corben Pittman

Corben Pittman

Skilled2021-05-11Added 83 answers


Given:
the wavelength of the sound will be
λ=vf
=345ms690Hz
a) for the first relative maximum we get
d1=d2+λ
from the figure using the pythagorous theorem we get
(d2+λ)2=d22+(0.820m)2
d2=
b) for the first relative minimum we get
d1=d2+(λ2)
from the figure using the pythagoroustheorem we get
(d2+(λ2))2=d22+(0.820m)2
d2=

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