NaF=0.10M MgCl_{2}=0.10M C_{2}H_{5}OH=0.10M CH_{3}COOH=0.10M Answer the following questions, which refer tothe 100mL samples of aqueous solutions at 25degrees Celcius.(solutions in stoppered flasks) (a) Which solution has the lowest electricalconductivity? Explain. (b) Which solution has the lowest freezingpoint? Explain. (c) Above which solution is the pressure of thewater vapor greatest? Explain. (d) Which solution has the highest pH?Explain.

NaF=0.10M MgCl_{2}=0.10M C_{2}H_{5}OH=0.10M CH_{3}COOH=0.10M Answer the following questions, which refer tothe 100mL samples of aqueous solutions at 25degrees Celcius.(solutions in stoppered flasks) (a) Which solution has the lowest electricalconductivity? Explain. (b) Which solution has the lowest freezingpoint? Explain. (c) Above which solution is the pressure of thewater vapor greatest? Explain. (d) Which solution has the highest pH?Explain.

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asked 2021-03-10
NaF=0.10M
\(\displaystyle{M}{g}{C}{l}_{{{2}}}={0.10}{M}\)
\(\displaystyle{C}_{{{2}}}{H}_{{{5}}}{O}{H}={0.10}{M}\)
\(\displaystyle{C}{H}_{{{3}}}{C}{O}{O}{H}={0.10}{M}\)
Answer the following questions, which refer tothe 100mL samples of aqueous solutions at 25degrees Celcius.(solutions in stoppered flasks)
(a) Which solution has the lowest electricalconductivity? Explain.
(b) Which solution has the lowest freezingpoint? Explain.
(c) Above which solution is the pressure of thewater vapor greatest? Explain.
(d) Which solution has the highest pH?Explain.

Answers (1)

2021-03-12
a)\(\displaystyle{C}_{{{2}}}{H}_{{{5}}}{O}{H}\) will have lowest ellectricalconductivity because it will not form ions in solutions.
b)\(\displaystyle{M}{g}{C}{l}_{{{2}}}\) has lowest freezing point because insolution \(\displaystyle{M}{g}{C}{l}_{{{2}}}\) gives more no. of particles.
c)\(\displaystyle{C}_{{{2}}}{H}_{{{5}}}{O}{H}\) has the highest vapour pressurebecause ethano will form less no. of particles in solution.
d)\(\displaystyle{M}{g}{C}{l}_{{{2}}}\) addition will shift the equilibrium \(\displaystyle{H}_{{{2}}}{O}\rightarrow{H}^{{+}}+{O}{H}^{{-}}\) because theformed \(\displaystyle{C}{l}^{{-}}\) will consume the \(\displaystyle{H}^{{+}}\) ions therebydecreasing its conc. which effectively increases \(\displaystyle{O}{H}^{{-}}\) concentration and pH.
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